WBJECA MCQ FOR NEW SYLLABUS
Operating System MCQ ( SET - 6)
- If the time quantum size is 2 unites of time and there is only one job of 14 time units in aready queue, the round-robin scheduling algorithm will cause ____________ context switches.
- 6
 - 7
 - 8
 - 5
 
Answer: A
Explantion: None - 'Aging' is _______________________ ?
- keeping track of cache contents
 - keeping track of waht pages are currently residing in memory
 - increasing the priority of jobs to ensure termination in a finite time
 - Both (B) and (C)
 
Answer: C
Explantion: None - A semaphore :
- must be accessed from only one process
 - can be accessed from multiple processes
 - is a binary mutex
 - all of these
 
Answer: B
Explantion: None. - The Processor is an example of computer _____________.
- program
 - software
 - hardware
 - none of these
 
Answer: C
Explantion: None - Resources are allocated to the process on non sharable basis is
- circular wait
 - no premtion
 - mutual exclusion
 - hold and wait
 
Answer: C
Explantion: None - Device drivers are that ____________
- short, special purpose programs
 - internal part of operating system
 - both (A) and (B)
 - none of above
 
Answer: A
Explantion: None - Usage of Pre-emption and Transaction Rollback prevents _________ ?
- Data manipulation
 - Unauthorized usage of data file
 - File pre-emption
 - Deadlock situation
 
Answer: D
Explantion: None - The Process Control Block is ________
- Data Structure
 - A Block In Memory
 - Process Type Variable
 - A Secondary Storage Section
 
Answer: A
Explantion: None - Simplest way of deadlock recovery is _________ ?
- preempt resource
 - Lock one of the processes
 - kill one of the processes
 - roll back
 
Answer: C
Explantion: None - 10Which of the following is incorrect for virtual memory ?
- More I/O is required
 - Faster and easy swapping of process
 - Large programs can be writen
 - More adderssable memory available
 
Answer: A
Explantion: None 
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